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x^2-1.1x-0.5=0
a = 1; b = -1.1; c = -0.5;
Δ = b2-4ac
Δ = -1.12-4·1·(-0.5)
Δ = 3.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.1)-\sqrt{3.21}}{2*1}=\frac{1.1-\sqrt{3.21}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.1)+\sqrt{3.21}}{2*1}=\frac{1.1+\sqrt{3.21}}{2} $
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